[squid-users] follow_x_forwarded_for to get client ip instead of sibling proxy

robert k Wild robertkwild at gmail.com
Thu Jan 16 17:05:07 UTC 2020

hi Alex,

thanks for the notes

so my child proxy, i have added -

#forward clients IP
forwarded_for on

and my parent -

acl my_other_proxy srcdomain
follow_x_forwarded_for allow my_other_proxy
log_uses_indirect_client on

but in my parent logs, im still getting the ip of the child proxy?

On Thu, 16 Jan 2020 at 16:47, Alex Rousskov <
rousskov at measurement-factory.com> wrote:

> On 1/16/20 9:59 AM, robert k Wild wrote:
> > i have two proxies (one sibling going to a parent)
> FYI: "siblings" are proxies that fetch hits from each other. The proxy
> "going to the parent" is usually called a "child" proxy:
>     clients -> child -> parent -> servers
> > when i look at the parent proxy access logs, it just logs the ip address
> > of the sibling proxy
> >
> > if i add the lines below in my sibling proxy
> >
> > acl localhost src
> > acl my_other_proxy srcdomain .proxy.example.com
> > follow_x_forwarded_for allow localhost
> > follow_x_forwarded_for allow my_other_proxy
> >
> > when i next look at the logs, will it show the ip of my clients?
> No, it will not (by default) AFAICT. For the parent proxy logs to
> contain IP addresses of the clients,
> a) The child proxy must send the X-Forwarded-For header to the parent.
> b) The parent proxy must trust X-Forwarded-For received from the child
>    (as far as logging is concerned).
> Your configuration changes at the child proxy do neither (a) nor (b).
> IIRC, (a) will happen by default, while (b) requires
> follow_x_forwarded_for and log_uses_indirect_client rules at the parent
> proxy.
>  I did not review your follow_x_forwarded_for rules.
> The follow_x_forwarded_for rules at the child proxy are needed if and
> only if you want the child proxy to trust the X-Forwarded-For headers
> received by that child proxy (from its clients). That is only necessary
> in deeper hierarchies:
>     clients -> child1 -> child2 -> parent
> Alex.


Robert K Wild.
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